Question

ʃ(x+4/x^2+5x+6) evaluate

Answer 1

=ʃ(x+4x^(-2)+5x+6 dx
=(x^2)/2+4(x^(-1))/(-1)+5(x^2)/2+6x+C
=1/2(x^2)-4/x+(5/2)x^2+6x+C

Answer 2

thank you I was confused with your format but at the end i think it was clear what you meant.
= ʃ(x+4)(x^(-2) +5x+6)dx
=(x^2 /2)+(4x^(-1) /(-1))+(5x^2 /2)+6x+c
=(1/2)x^2 -(4/x)+(5/2)x^2 +6x+c
correct?

Answer 3

yeap, that's what I meant.