Question

A trigonometric question:
On an ABC triangle , the edges are a, b and c.
(b-c)/(b+c)=1/(root3)
m(A)=60 degree angle

what is angle of m(B) ?

Answer 1

if its a right triangle, then the m(B) will equal 30 degrees.

if its not a right triangle, then a picture would be helpful

Answer 2

There is no given shape.Thanks anyway.

Answer 3

Answer is equal 105 degrees.

Answer 4

then you could do it the hard way by making a system of equations:

b - c = 1
b + c = sqrt(3)

and finding your b and c....

Answer 5

then use the law of cosines to find "a" and the law of sines to find all your angles

Answer 6

b = 1+c

(1+c) +c = sqrt(3)

1 + 2c = sqrt(3)

2c = sqrt(3)-1

c = (sqrt(3)-1)/2; b = (1 + sqrt(3))/2

Answer 7

I found a=6 then
I found , 12/sqrt(3)=(sqrt(3)-1)/sin(B) But couldn't go further

Answer 8

if your a=6 is good; then:

sinA sinB)
---- = -----
a b

sinB = b sin(A)/a

Answer 9

sinB = [ (1 + sqrt(3))/2 ] [sqrt(3)/2] / 6

sinB = (sqrt(3) +3)/24

Answer 10

sinB = sqrt(3)/24 + 1/8

Answer 11

the sin inverse funtion will give you one angle for that taio; but you have to be aware that 2 angles are possible with a positive sin.

Answer 12

taio means ratio..... somehow :)

Answer 13

Prof ,My problem is how can i turn this to degree. :)

Answer 14

with the sin inverse function on a calculator.

Answer 15

I got it , sin inverse function , i will try thanks :)