how would you integrate the sqrt of
(9-x^2) from -3 to 3 . i tried trig sub with x = to 3 sin theta but i get a wrong answer at the end; it get 0

Question

how would you integrate the sqrt of 
(9-x^2) from -3 to 3 . i tried trig sub with x = to 3 sin theta but i get a wrong answer at the end; it get 0

amistre64 · Answer

you will always get a zero.... becuase the left side cancels out the number for the right side

amistre64 · Answer

you either need to move the graph itself to the right by 3 units and adjust the equation;

or integrate half of it: from 0 to 3 and then double your result.

amistre64 · Answer

or you could do F(a) - F(b) instead and take the absolute value

amistre64 · Answer

4 - 4 = 0

-4 -(4) = -8

|-8| = 8

anonymous · Answer

The left side doesnt cancel the right side. It's an even function, you just did the integral wrong.

anonymous · Answer

no is was suposed to use the power reduction formulas
for cos squared

anonymous · Answer

after you realize that step the problem is solved

anonymous · Answer

thanks you guys!

amistre64 · Answer

huh... i guess I need to review that part ;)  thanx space