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OpenStudy (anonymous):
How do I solve (1+3i)/(4 + 3i) and put the answer in a + bi form???
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OpenStudy (anonymous):
Firstly you should multiply both part with divisor's conjugate , (4+3i)'s conjugate is 4-3i (always opposite sign of imaginal number) (1+3i)(4-3i)/(4+3i)(4-3i)=(13+9i)/25
OpenStudy (anonymous):
Got it, thanks!
OpenStudy (anonymous):
Got it, thanks!
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