Question

the center for disease control reports that 24.8 percent of californians are obese. a sample of 112 california residents is taken. what is the probability that over 30 percent of the sample is obese?

Answer 1

so basically i know the mean is 27.78 and the std deviation is 4.57...now what

Answer 2

30% of 112 is 33.6
now you want to find out how many std dev's away this is from the mean
z = (33.6-27.78)/4.57 = 1.27
now you have to look in a stats z table for probabilities of the standard normal distribution
1 - P(Z<= 1.27)