Question

deriviative of y= -Ae^-t (Sint - cost)

Answer 1

A constant?

Answer 2

What do you mean? A is a constant yes

Answer 3

y=-A(e^-t)(sint-cost)
y=-A(e^-t)sint + A(e^-t)cost
y'=-Ad/dt((e^-t)sint)+Ad/dt((e^-t)cost)

d/dt ((e^-t)sint) =(e^-t)cost + (-e^-t)sint
d/dt ((e^-t)cost)=(e^-t)(-sint) + (-e^-t)cost

y'=A(-((e^-t)cost + (-e^-t)sint)+(e^-t)(-sint) + (-e^-t)cost)
y'=A(-(e^-t)cost + (e^-t)sint + (e^-t)(-sint) - (e^-t)cost)
y'=A(-2(e^-t)cost)=-2A(e^-t)cost

Answer 4

Ahhhh yes thanks alot :)

Answer 5

no prob

Answer 6

btw can you guess what level calculus this is?

Answer 7

I would say end of 1st year uni or beginning of 2nd year, if that's what you mean by level.

Answer 8

im doing this in my senoir year of highschool :( my teacher is crazyyyy

Answer 9

I got expelled :D:D:D hate those highweeded teachers