Question

I need to do a laplace transform of sin((pi)t)... any suggestions?

Answer 1

\[L[sint (at)]= \frac{a}{s^2+a^2} \]
In your case a=pi
\[[L[sint (\pi t)]= \frac{\pi}{s^2+\pi^2}\]

Answer 2

ah, thanks. i just found that in the book as well. easier than it looked!

Answer 3

no problem