Question

150.0 g of AsF3 was reacted with 180.0 g of CCl4 to produce AsCl3 and CCl2F2. The theoretical yield of CCl2F2 produced, in moles, is?

a]0.7802 mol
b]1.274 mol
c]1.170 mol
d]0.5685 mol
e]1.705 mol

Answer 1

AsF3 + CCl4 = AsCl3 + CCl2F2
you need all the mol number of each substance of both sides to be equal.
start with F
3F on the left, 2F on the right
so time 2 to 3F on the left, time 3 to 2F com the right, we get
2AsF3 + CCl4 = AsCl3 + 3CCl2F2
Now, there are 2 As on the left, 1 As on the right so time 2 to As on the right to balance
2AsF3 + CCl4 = 2AsCl3 + 3CCl2F2
now there are 4Cl left, 12Cl right, also 1C left, 3C right
so time 3 to CCl4
2AsF3 + 3CCl4 = 2AsCl3 + 3CCl2F2
that's the balance part

Answer 2

when u get used to it, u will just put number in there by trying, shouldn't take more than 30 secs.

Answer 3

Wow... what do I do afterwards?

Answer 4

Now group what information you have
M: atomic mass, u know this.
n: mol number

150.0 g of AsF3
MAs=75g/mol
MF=19g/mol
MAsF3=75+19*3=132g/mol
nAsF3=150/132=1.136mol

180.0 g of CCl4
MC=12
MCl=35.5
MCCl4=12+35.5*4=154
nCCl4=180/154=1.169mol

Answer 5

Thank you so much :) Now you can go back to bed :P

Answer 6

2AsF3 + 3CCl4 = 2AsCl3 + 3CCl2F2
theoretically 2mol 3mol don't need 3mol
reality 1.136 1.169
should be 1.132 -> 1.704
try with CCl4 1.169





blabla, so you can take over from here right? i'll leave the rest for you

Answer 7

no prob