Question

i need help.....

Answer 1

With what?

Answer 2

\[f"(x)=4x+3\] and \[f'(-3)=-1\] and f(-3)=0 find f'(x) and f(1)

Answer 3

You take the Integral of the equations so... to get \[f \prime(x)= 4x/2 +3x +c\] where c is a constant. You then plug it in for x=-3 to solve for the constant...
You repeat this on f'(x) to then find f(x)

Answer 4

ok i go f'(x)=2x^2-3x-28

Answer 5

Athens got it good :) little typo ish, but good...

Answer 6

then \[f(x)=(2/3)(x^3)-(3/2)(x^2)-28x+c\]