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bsqrt(2)=sqrt(4b-2)
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(b)sqrt(2)=sqrt(4b-2)
Did you try squaring both sides?
That will work, but you have to restrict the definition set of b.
yeah but got a bit confused by the first b
\[b\sqrt{2} = \sqrt{4b-2}\] \[\implies (b\sqrt{2})^2 = (\sqrt{4b-2})^2\] \[\implies b^22 = 4b-2 \text{, for }b>\frac{1}{2}\] etc.
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what would the next step be then?
divide by the 2 or add the two
Moving everything to one side to get the equation equal to 0, then use the quadratic equation.
oooh thank you! what about that first two though?
b=2?
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If you want to divide the whole thing by 2 you certainly can.
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