Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

bsqrt(2)=sqrt(4b-2)

OpenStudy (anonymous):

(b)sqrt(2)=sqrt(4b-2)

OpenStudy (anonymous):

Did you try squaring both sides?

OpenStudy (nowhereman):

That will work, but you have to restrict the definition set of b.

OpenStudy (anonymous):

yeah but got a bit confused by the first b

OpenStudy (anonymous):

\[b\sqrt{2} = \sqrt{4b-2}\] \[\implies (b\sqrt{2})^2 = (\sqrt{4b-2})^2\] \[\implies b^22 = 4b-2 \text{, for }b>\frac{1}{2}\] etc.

OpenStudy (anonymous):

what would the next step be then?

OpenStudy (anonymous):

divide by the 2 or add the two

OpenStudy (anonymous):

Moving everything to one side to get the equation equal to 0, then use the quadratic equation.

OpenStudy (anonymous):

oooh thank you! what about that first two though?

OpenStudy (anonymous):

b=2?

OpenStudy (anonymous):

If you want to divide the whole thing by 2 you certainly can.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!