Question

I need to solve this, then graph it.
y=x^-6x+8

Answer 1

x^2-6x+8 or x^-6x+8 ?

Answer 2

its a parabola

Answer 3

I asked if \[x ^{2}-6x+8\] or \[x ^{-6x}+8\] ?

Answer 4

x squared

Answer 5

Im trying to figure out how to solve that parabola in standard form

Answer 6

y= (x-4)(x-2) those are your zero points for y

Answer 7

And to graph it , you may need vertex ,for f(x)=ax^2+bx+c , vertex is (-b/2a,f(-b/2a))

Answer 8

you should write your equation in a complete square form, that's:
\[y=(x-3)^2-1\]
the vertex is (3,0)

Answer 9

ok how to solve : to find x the x interecepts and y intercept

Answer 10

x intercepts and y intercepts

Answer 11

To find x intercepts , suppose y=0 , y=(x-4)(x-2) so (x-4)(x-2)=0 , x intercepts are 4 and 2
To find y intercept , plug in 0 to x so -4*-2=8

Answer 12

to find y-int plug x=0, and to find x-int plug y=0. you will get
y-int (0,8).. and two x-int (4,0), (2,0)

Answer 13

I cannot do that because x and x sqaured arent like terms?