Simplify the trigonometric expression. csc(x) - sin(x) / cot(x)
[1/sin(x)-1/sin(x)]/(1/tan(x)) = tan(x)
did we recall what this clean up to be? if its "all over" cot(x) you can writ eit like this: csc(x) - sin(x) // cot(x) that "//" will tell me that its a loner fraction bar
longer fraction bar
ok
csc sin --- - --- cot cot 1/sin sin ------ - ------- cos/sin cos/sin
sec(x) - tan(x)csc(x) is what I get if I read it right
are the tan[x] and csc[x] seperated by anything or r they together
whoops: [1/sinx-sinx/1]/1/tanx = tanx
let me see this one more time...
still wrong yeska
1/sinx - sinx/1 equals 1
than multiply by reciprocal, = tanx?
My hw program says it's wrong
1 sin sin --- - ------- cos cos sec(x)(1 - sin^2) sec(x) cos^2(x) 1 cos cos -------- = cos(x) cos
try that
And you are correct... like always :)
Write the trigonometric expression in terms of sine and cosine, and then simplify. sec(x)/csc(x)
1 --- cos ----- = sin/cos = tan(x) 1 --- sin
damn
lol ...stub your toe?
no... the answer was fast but the program says it's wrong
nvm, got the answer.
Use an addition or subtraction formula to find the exact value of the expression. sin(285)
What is the answer to this problem?
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