Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

Simplify the trigonometric expression. csc(x) - sin(x) / cot(x)

OpenStudy (anonymous):

[1/sin(x)-1/sin(x)]/(1/tan(x)) = tan(x)

OpenStudy (amistre64):

did we recall what this clean up to be? if its "all over" cot(x) you can writ eit like this: csc(x) - sin(x) // cot(x) that "//" will tell me that its a loner fraction bar

OpenStudy (amistre64):

longer fraction bar

OpenStudy (anonymous):

ok

OpenStudy (amistre64):

csc sin --- - --- cot cot 1/sin sin ------ - ------- cos/sin cos/sin

OpenStudy (amistre64):

sec(x) - tan(x)csc(x) is what I get if I read it right

OpenStudy (anonymous):

are the tan[x] and csc[x] seperated by anything or r they together

OpenStudy (anonymous):

whoops: [1/sinx-sinx/1]/1/tanx = tanx

OpenStudy (amistre64):

let me see this one more time...

OpenStudy (anonymous):

still wrong yeska

OpenStudy (anonymous):

1/sinx - sinx/1 equals 1

OpenStudy (anonymous):

than multiply by reciprocal, = tanx?

OpenStudy (anonymous):

My hw program says it's wrong

OpenStudy (amistre64):

1 sin sin --- - ------- cos cos sec(x)(1 - sin^2) sec(x) cos^2(x) 1 cos cos -------- = cos(x) cos

OpenStudy (amistre64):

try that

OpenStudy (anonymous):

And you are correct... like always :)

OpenStudy (anonymous):

Write the trigonometric expression in terms of sine and cosine, and then simplify. sec(x)/csc(x)

OpenStudy (amistre64):

1 --- cos ----- = sin/cos = tan(x) 1 --- sin

OpenStudy (anonymous):

damn

OpenStudy (amistre64):

lol ...stub your toe?

OpenStudy (anonymous):

no... the answer was fast but the program says it's wrong

OpenStudy (anonymous):

nvm, got the answer.

OpenStudy (anonymous):

Use an addition or subtraction formula to find the exact value of the expression. sin(285)

OpenStudy (anonymous):

What is the answer to this problem?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!