Question

Simplify the trigonometric expression.

cos[x]/sec[x] + sin[x]/csc[x]

Answer 1

help

Answer 2

secx = (1/cosx)
cscx =(1/sinx)

therefore
cos[x]/sec[x] + sin[x]/csc[x] = (cosx)^2 + (sinx)^2 = 1

Answer 3

The expression simplifies to 1. It is found in the following manner: sec[x] is 1/cos[x] which makes the first term = (cos[x]) (cos[x]) = cos^2[x]; and csc[x] is 1/sin[x] which makes the second term = (sin[x]) (sin[x]) = sin^2[x]). The expression now becomes cos^2[x] + sin^2[x] = 1.

Answer 4

thanks