Question

I am doing quadratic functions Can someone help me solve this
y=-2x^2+11x-12

Answer 1

Solve it for y = 0? Are you familiar with the quadratic formula?

Answer 2

yes but this is +or - a=-2,b=11 c=-12

Answer 3

I know how to do the formula but have done 10 problems but don't come up with the correct answer

Answer 4

Those are the correct values for a, b, and c.

Answer 5

\[11+-\sqrt{(11^2-4(-2)(-12)}\]

Answer 6

I have done the numbers in parenthesis first what do you come up with

Answer 7

\(11^2 - 4(-2)(-12) = 25\)

Answer 8

okay that is what I got

Answer 9

x=4

Answer 10

So you should have
\(\frac{-11 \pm \sqrt{25}}{2(-2)}\)

Answer 11

I have to have a + and - answer

Answer 12

They could both be + or - depending on your other values.

Answer 13

But you will have 2 unless the part under the sqrt is 0

Answer 14

I have \[11+-\sqrt{25?}\div-4\]

Answer 15

It should be -11, not 11. Recall that the quadratic formula is

\[ax^2 + bx +c=0 \implies x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 16

i got x=-9 and -14 over-4

Answer 17

okay that is right I have it in front of me

Answer 18

x = (-11 + 5 )/(-4) = -6/-4 = 3/2
x = (-11 - 5)/(-4) = -16/-4 = 4

Answer 19

if you let y be 0 than after you can write your equation as -2x^2+11x-12=0 or you can write this as 2x^2-11x+12=0 from this equation you can get the correct answer

Answer 20

You won't have any negative values for the x intercepts of this graph.

Answer 21

True I have been working on this too long I think thank you

Answer 22

Certainly =)