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OpenStudy (gerald):

find the derivatives of x4+x3-2x2/x+2

OpenStudy (anonymous):

first do the long divison and then use partial fraction method to integrate

OpenStudy (gerald):

pliz can you do that for me

OpenStudy (anonymous):

where are you avnis chat box is broken

OpenStudy (anonymous):

hey i am here

OpenStudy (anonymous):

hey

OpenStudy (anonymous):

so that length question i think i solved it

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so working on this question i know you can find common terms in this question i am just trying to find that

OpenStudy (anonymous):

i mean i am refering to gerald's question

OpenStudy (anonymous):

lets do long division

OpenStudy (anonymous):

hmm okay, but i was thinking if we just rearrange and ge trid of the common terms

OpenStudy (anonymous):

here http://www.skrbl.com/166859043

OpenStudy (anonymous):

sorry here http://www.skrbl.com/166859043

OpenStudy (anonymous):

sorry again here

OpenStudy (anonymous):

i hope that works

OpenStudy (gerald):

can those link lead me to answer

OpenStudy (anonymous):

yes im typing solution

OpenStudy (anonymous):

did it work

OpenStudy (anonymous):

oh i solve dit on the the other one :P

OpenStudy (anonymous):

hehe, its not bad

OpenStudy (anonymous):

http://www.skrbl.com/166859043

OpenStudy (anonymous):

you get integral x^3 - x^2

OpenStudy (anonymous):

so basically gotta integrate x^3 -x^2

OpenStudy (anonymous):

and that will give you ((x^4)/4)-(x^3/3) + C

OpenStudy (anonymous):

yes

OpenStudy (gerald):

those site are not active

OpenStudy (anonymous):

u just want to find the first derivative right?

OpenStudy (anonymous):

are we talking about derivatives or integrals? because you just integrated

OpenStudy (anonymous):

uhm cantorset...do you know what you are talking about?

OpenStudy (anonymous):

according to the questions, it says "derivatives" , right?

OpenStudy (anonymous):

you can use the quotient rule to solve this if you like

OpenStudy (anonymous):

do ther derivative with quotient rule. ((x+2)(4x^3+3x^2-2x^2)-(x^4+x+3-2x^2))/(x+2)^2

OpenStudy (anonymous):

that is the correct approach, ignore whatever cantorset mentioned its nonsense

OpenStudy (anonymous):

d/dx of f(x)/g(x)=( f'(x)g(x)-f(x)g'(x))/(g(x))^2

OpenStudy (anonymous):

okay, so when u want to find the derivative, here , its better if u use the 'u/v' rule.. which is \[(v u \prime-u v \prime )/v ^{2}\]

OpenStudy (anonymous):

wher u =numerator & v=denominator

OpenStudy (anonymous):

exactly, thats correct @avalanche :)

OpenStudy (anonymous):

great minds think alike :)

OpenStudy (anonymous):

yupp :):)

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