find the derivatives of x4+x3-2x2/x+2
first do the long divison and then use partial fraction method to integrate
pliz can you do that for me
where are you avnis chat box is broken
hey i am here
hey
so that length question i think i solved it
ok
so working on this question i know you can find common terms in this question i am just trying to find that
i mean i am refering to gerald's question
lets do long division
hmm okay, but i was thinking if we just rearrange and ge trid of the common terms
sorry again here
http://www.scriblink.com/index.jsp?act=phome&roomid=36&KEY=F71D8E165FCC9B3AA0E17782EDB164F0
i hope that works
can those link lead me to answer
yes im typing solution
http://www.scriblink.com/index.jsp?act=phome&roomid=36&KEY=F71D8E165FCC9B3AA0E17782EDB164F0
did it work
here im over here http://www.scriblink.com/index.jsp?act=phome&roomid=36&KEY=F71D8E165FCC9B3AA0E17782EDB164F0
oh i solve dit on the the other one :P
hehe, its not bad
you get integral x^3 - x^2
so basically gotta integrate x^3 -x^2
and that will give you ((x^4)/4)-(x^3/3) + C
yes
those site are not active
u just want to find the first derivative right?
are we talking about derivatives or integrals? because you just integrated
uhm cantorset...do you know what you are talking about?
according to the questions, it says "derivatives" , right?
you can use the quotient rule to solve this if you like
do ther derivative with quotient rule. ((x+2)(4x^3+3x^2-2x^2)-(x^4+x+3-2x^2))/(x+2)^2
that is the correct approach, ignore whatever cantorset mentioned its nonsense
d/dx of f(x)/g(x)=( f'(x)g(x)-f(x)g'(x))/(g(x))^2
okay, so when u want to find the derivative, here , its better if u use the 'u/v' rule.. which is \[(v u \prime-u v \prime )/v ^{2}\]
wher u =numerator & v=denominator
exactly, thats correct @avalanche :)
great minds think alike :)
yupp :):)
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