Question

For what values of x does the series P1n =1
(x−5)n
n2n converge absolutely?
converge conditionally? diverge? how do you even start this thing ?????

Answer 1

i cant read this, are those subscripts

Answer 2

P ln ?

Answer 3

how do you add mayh symbols

Answer 4

math *

Answer 5

subscripts you can write a_n , or underscore

Answer 6

they are superscripts and i also need to add a sigma sign

Answer 7

superscripts is like exponent ^

Answer 8

ohk i will just write so we have a fraction ((x-5)^5)/(n2^n) and sigma n=1 to infinity

Answer 9

∑n=1 to infinity for ((x-5)^5)/(n2^n)

Answer 10

when x =0 clearly it converges

Answer 11

i mean when x = 5

Answer 12

when x is even you have

Answer 13

when x > 5 it converges absolutely

Answer 14

why would you say when x>5 it converges

Answer 15

then its positive the numerator

Answer 16

i think theres something wrong with the series
i get for all x it converges

Answer 17

hmm i wasthinking if x>5 then it will diverge because numerator will be positive and growing :|

Answer 18

and for 5 it is zero converges and then after that it negative growth

Answer 19

no it will be constant

Answer 20

remember the variable is n here inside the series

Answer 21

so if x = 10, you have (10-5)^5 or 5^5 in the numerator

Answer 22

oh wait a second

Answer 23

you typed the question wrong

Answer 24

hmm ya i didn't pay attention to that :|

Answer 25

it should be (x-5)^n / ( 2^n ) ?

Answer 26

the series

Answer 27

(x-5)^n / ( n2^n ) there is a n in front of 2 :|

Answer 28

oh ok, so now its tougher

Answer 29

wait up i am going to put up a screen shot :)

Answer 30

oh ok

Answer 31

they are asking for a radius of convergence

Answer 32

hmm i thought we need to find limits :|

Answer 33

so we can use the ratio test

Answer 34

yes i think we can :)

Answer 35

ok so we can use our scriblink

Answer 36

which one

Answer 37

http://www.scriblink.com/index.jsp?act=phome&roomid=44&KEY=F71D8E165FCC9B3AA0E17782EDB164F0