Question

attention amistre64!!

Answer 1

I have a question of vectors and i need help with that. so can you plz spare some time on it? i am attaching the question below

Answer 2

vectors eh.... i was trying to catch up on them last night, little arrows with direction and magnitude...<x,y>

Answer 3

so what is a vector normal to the surface like? anything like a position vector in R^2?

Answer 4

oh nevermind. "lokisan" has already answered it =) i'll post the link and u can see it

Answer 5

http://openstudy.com/groups/mathematics#/updates/4da986dfd6938b0b56a2a54d

Answer 6

thanks :) Im still wet behind the ears when it comes to adding the zplane ;)

Answer 7

normal to the surface means perpendicular to the surface

Answer 8

yes.

Answer 9

the ijk in there are vector identifiers right?

Answer 10

yes.

Answer 11

correspond with xyz if I recall correctly

Answer 12

but then i do not recall correctly lol... we foil out the left part right?

Answer 13

does 3x^2 (xi) = 3x^3 i?

Answer 14

i would suggest you revise it =)

Answer 15

lol.... give me a week, and ill be a pro at it :) but for know, its over me head

Answer 16

sorry can't wait that long =)

Answer 17

you tell me the steps you took and ill see if I cant mess them up ... sound good?

Answer 18

cross product sounds familiar.....

Answer 19

ab = absin(t)n is looking good to me

Answer 20

To find Normal vector find r'(v)/||r'(v)||

Answer 21

In this specific case you find the del

Answer 22

||r'V|| is the length or magnitude.... of the vector , i think

Answer 23

You find the dell and it leads to a messy vector. Normal is <x/(16x^2+16y^2+1), 3/(16x^2...), sq rt (16x^2...)/sq rt (x^2+y^2). I have no reason why they would ask a question that would get such a result unless it is a challenge or competition question.