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Mathematics 20 Online
OpenStudy (anonymous):

Determine if the sequence (cosn/ n) converges or diverges.

OpenStudy (anonymous):

converges

OpenStudy (anonymous):

but how that is the question

OpenStudy (anonymous):

squeeze theorem

OpenStudy (anonymous):

i mean i know becaus ei can see i just don't know how to do the math

OpenStudy (anonymous):

i.e. \[-1\leq \cos n\leq 1\]

OpenStudy (anonymous):

\[\frac{-1}{n}\leq \frac{\cos n}{n}\leq \frac{1}{n}\]

OpenStudy (anonymous):

take its limit Lim(cosn/n)=0 when n goes to infinite so that it is convergence

OpenStudy (anonymous):

since \[lim_{n\rightarrow \infty}\frac{-1}{n}=\lim_{n\rightarrow \infty}\frac{1}{n}=0\]

OpenStudy (anonymous):

ah that makes sense

OpenStudy (anonymous):

so by sqeezing \[\lim_{n\rightarrow \infty}\frac{\cos n}{n}=0\]

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