Question

8= 5+ 2log(x/4)....solve for x

Answer 1

subtract 5 from both sides of the equation and post what you got.

Answer 2

3=2log(x/4)

Answer 3

divide 2 on both sides and post what you got.

Answer 4

3/2=log(x/4)

Answer 5

now take inverse log on both sides.

Answer 6

i dont know how

Answer 7

okay, \[\log_{a}x =y \rightarrow x = y^{a} \]

Answer 8

so x=3/2^4

Answer 9

no, the natural log, ln is generally to the base e, that is,
\[\ln =\log_{e} \]
whereas when you see log in a problem, it generally to the base 10. that is,
\[\log_{} = \log_{10} \]

Answer 10

im confused on what it would look like

Answer 11

so, if you know that \[\log_{a} x=y→x=y^{a}\]
and

Answer 12

\[\log_{10}(x/4) = 3/2 \rightarrow x/4 = ?\]

Answer 13

3/2^10

Answer 14

whoops my mistake.
\[\log_{a}x = y \rightarrow x = a ^{y} \]

Answer 15

ok got it thanks

Answer 16

you are welcome.

Answer 17

for example, \[\log_{10}1000 = 3 \]
why?
because \[10^{3} = 1000\]

Answer 18

i have another

Answer 19

similarly
\[\log_{10}64 = 1.80 \]

why?
because
\[10^{1.8} = 64\]

Answer 20

do you understand the concept of logarithms?

Answer 21

yes i do property of logs

Answer 22

not the properties, do you understand the fundamental concept of logs?

Answer 23

log base 5 (3x+10) -3 log base 5 (4)=2.......yes i do!

Answer 24

okay great!

Answer 25

could u help me with that problem

Answer 26

log a + log b = ?

Answer 27

log a time b

Answer 28

and log a - log b = ?

Answer 29

divide

Answer 30

a log b?

Answer 31

logb^a

Answer 32

ok so what is 3 log 4?

Answer 33

64

Answer 34

what?

Answer 35

are you sure?

Answer 36

log64

Answer 37

okay good
so what is log(3x+10)-log64?

Answer 38

log has a base of 5 on both

Answer 39

\[\log_{5} \]

Answer 40

yes.

Answer 41

so what?

Answer 42

im confused from there

Answer 43

log(3x+10)/64

Answer 44

okay, when you say
\[\log A+\log B = \log(A*B) \],
what you really mean is \[\log_{x}A+\log_{x}B = \log_{x}AB \]

Answer 45

well division

Answer 46

so only if your bases are the same, you can perform logarthmic arithmetic.

Answer 47

yea

Answer 48

so your equation now becomes
\[\log_{5}((3x+10)/64 ) = 2\]

Answer 49

we know that
\[\log_{a}x = y \rightarrow x = a ^{y}\]

Answer 50

ok

Answer 51

so what is 3x+10/64 = ?

Answer 52

25

Answer 53

so 3x+10 = ?

Answer 54

ok got it thank u again

Answer 55

you are welcome.

Answer 56

ok so i am stuck on another i am at x+4(x-1)=36