4/5(2x-1)>12
Are you solving for x?
Excuse me, is it (4/5)*(2x-1)>12 or 4/[5(2x-1)]>12? could you make that clearer
if it is (4/5)*(2x-1)>12 then x>8; if it is 4/[5(2x-1)]>12 then x>(4/5)
Yes, solving for x, and the first of the options is what it is supposed to be. :Thank you. :)
It told me the answer was incorrect. :( Here is a similar equation, with as far as I can get on my own: 2/3(3x-6)>12 6/3x-12/3>12 12(6/3x-12/3)>12(12) (72/3)x-(144/3)>144 I can not seem to get to the answer from here. I'm sure it's probably easy, but I need it explained in simple terms.
2/3(3x-6)>12 3x-6>18 3x>24 x>8
Also needing assistance with compound inequalities. Will be posting one soon. I don't just want an answer. I want someone to teach me (simply) how to solve them, step-by-step. Note: The compound inequalities have some odd fractions, so I may have to explain them differently.
Dhat: Where did the 2/3 go?
I multiplied by 3/2 on both sides.
OK, I see. Thank you. :)
you are welcome
Would you like me to post the compund inequality here, or as a new question?
new thread please
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