Question

256^4x=64^x+3

Answer 1

take log on both sides and solve

Answer 2

do you know how to take log?

Answer 3

Or you can simply make the base the same

Answer 4

just what mooolen said
256 = 4^4
64 = 4^3
->4^16x = 4^(3x+9)

Answer 5

wait, is the +3 on the exponent of 64 or ist it (64^x) +3? If it is the former, then do what moolen said.

Answer 6

\[256^{4x}=64^x+3\]\[256^4x - 64^x = 3\]\[4^{4(4x)} - 4^{3x} =3\]\[4^{16x} - 4^{3x} =3\]\[4^{16x} - 4^{3x} =3 + 1 - 1\]\[4^{16x} - 4^{3x} =4^1 - 4^0\]
since they all got same bases, you can simply equate the exponents.
\[16x - 3x = 1-0\]
\[x = 1/13\]
NOT SURE IF I'VE DONE IT RIGHT. HOPE IT HELPED YOU.

Answer 7

Sorry. I think I'm wrong

Answer 8

256^(4x) = 64^(x+3) ???

Answer 9

its hard to tell how the problem reads to begin with...

Answer 10

i think the answer is x=0,9/13

Answer 11

thats possible, but whats the question to begin with?

Answer 12

256^(4x) = 64^(x+3)

4x log2(256) = (x+3) log2(64)

4x log2(64)
----- = --------
(x+3) log2(256)
----------------------

4x = log2(64)

x = log2(64)/4
--------------------

x+3 = log2(256)

x = log2(256) -3

Answer 13

if anything x = 9/13 :) if i see your question correctly

Answer 14

if x = 0 the you get 1 = 64^3 which is not right