Mathematics
54 Online
OpenStudy (anonymous):
Multiply:
1.) [sqrt.2x^2] * [10x^6]
2.) [2x sqrt.12x] * [3 sqrt.4x]
3.) 6 sqrt.5 ( [srt.11] + [sqrt.5] )
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
please help
OpenStudy (anonymous):
It's impossible to solve it. You need to make it more clear. Try using the equation button or taking a picture of the questions and attaching it here.
OpenStudy (anonymous):
^ = to the power
sqrt. = that square root sign
OpenStudy (anonymous):
oh nevermind i just saw the eqaution button , holdon
OpenStudy (anonymous):
Yeah, but would it be \[\sqrt{(2x)^{2}} * (10x)^{^{6}}\]
or
\[(\sqrt{2x})^{^{2}}*10x ^{6}\]
?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[1.) \sqrt{2x ^{2}} \times \sqrt{10x ^{6}}\]
OpenStudy (anonymous):
2.) \[(2x \sqrt{12x} ) (3\sqrt{4x})\]
OpenStudy (anonymous):
3.) \[6\sqrt{5} (5\sqrt{11} + \sqrt{5})\]
OpenStudy (anonymous):
\[\sqrt{2} x * \sqrt{10} x ^{3}\]
\[2 \sqrt{5} x ^{4}\]
OpenStudy (anonymous):
ok now?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
why wouldn't it be \[2x ^{2}\sqrt{5}\]
OpenStudy (anonymous):
nevermind, I thought the x^4 was in the sqrt.
OpenStudy (anonymous):
well khmath i think your right
OpenStudy (anonymous):
oh never mind neither answers show here
OpenStudy (anonymous):
would it be \[2x ^{4} \sqrt{5}\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
?
OpenStudy (anonymous):
yes..
OpenStudy (anonymous):
and for the rest of the problems ?
OpenStudy (anonymous):
u figured out the second one ...right??/
OpenStudy (anonymous):
it wasnt right
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i just was asking if it was
OpenStudy (anonymous):
ok lets do it again...
OpenStudy (anonymous):
are you sure you know how to do this ?
OpenStudy (anonymous):
yes i do
OpenStudy (anonymous):
ok just making sure
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
4sqrt(3) x * sqrt(x) * 6 * sqrt(x)
24 sqrt(3) *x
OpenStudy (anonymous):
mm.. 24 sqrt(3) *x * sqrt(x)
OpenStudy (anonymous):
for the second ?
OpenStudy (anonymous):
ya
OpenStudy (anonymous):
no it doesnt give that answer here as an option :/
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
wait i dont get which one you wrote
OpenStudy (anonymous):
the second one
OpenStudy (anonymous):
but which was your answer
OpenStudy (anonymous):
let me rewrite again
OpenStudy (anonymous):
one min
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
24 sqrt3 x^2
OpenStudy (anonymous):
final answer...
OpenStudy (anonymous):
now first two are solved...okay?
OpenStudy (anonymous):
\[24\sqrt{3x ^{2}}\]
OpenStudy (anonymous):
?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
no ...x^2 is not under the square root
OpenStudy (anonymous):
so just 3x alone ?
OpenStudy (anonymous):
wait a sec
OpenStudy (anonymous):
hmmmm
OpenStudy (anonymous):
\[24 \sqrt{3} \]\[x ^{2}\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
they r together
OpenStudy (anonymous):
x goes before where ?
OpenStudy (anonymous):
doesnt matter where u write x ,
OpenStudy (anonymous):
thanks , but nevermind i really dont think you know how to this . to many attempts , but thanks for trying to help