Mathematics
8 Online
OpenStudy (anonymous):
1.) 6 sqrt.5 ( [srt.11] + [sqrt.5] )
2.) (3 sqrt.3 +3 )(6 sqrt. 3 + 2)
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OpenStudy (anonymous):
1.) \[6\sqrt{5} ( \sqrt{11} + \sqrt{5})\]
OpenStudy (amistre64):
what do you come up with when you distribute it thru?
OpenStudy (anonymous):
2.) \[(3\sqrt{3} + 3) (6\sqrt{3} + 2)\]
OpenStudy (anonymous):
what do you mean ?
OpenStudy (amistre64):
I mean that you need to know what the distributive property is so you can solve these for yourself ;)
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OpenStudy (amistre64):
if you want to learn, I can teach you :)
OpenStudy (amistre64):
and posting 2 questions at a time tends to mean you just want someone else to do your homework for you.....
OpenStudy (anonymous):
\[2.) 6 + 18\sqrt{3}^{2} + 6\sqrt{3} \]
OpenStudy (anonymous):
i think thats the answer
OpenStudy (anonymous):
and no its not homework its an exam for my course
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OpenStudy (amistre64):
its a good start.... but lets check it out...
OpenStudy (anonymous):
i dont think i can simplify it more ?
OpenStudy (amistre64):
(3 sqrt.3 +3 )(6 sqrt. 3 + 2)
3sqrt(3) (6sqrt(3)) = 18(3)
3(2)sqrt(3) = 6sqrt(3)
3(6sqrt(3)) = 18sqrt(3)
3(2)=6
OpenStudy (anonymous):
so im right ? :)
OpenStudy (amistre64):
54+6 +24sqrt(3)
60 + 24sqrt(3) if I did it right :)
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OpenStudy (amistre64):
you had 3 terms good, but were missing that forth
OpenStudy (amistre64):
12(5 + 2sqrt(3)) is another way to write it
OpenStudy (anonymous):
ohhh true ! and for the 1st problem i got \[6\sqrt{11} + 5\]
OpenStudy (anonymous):
im not sure if its right ?
OpenStudy (amistre64):
I got:
6sqrt(55) + 30
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OpenStudy (amistre64):
\[6\sqrt{5*11} + 6\sqrt{5*5}\]
OpenStudy (anonymous):
ahhh true , i thought i was just suppose to cancel it out
OpenStudy (amistre64):
\[6\sqrt{55} + 6(5) = 6\sqrt{55}+30\]
OpenStudy (anonymous):
\[(2x \sqrt{12x}) (3\sqrt{4x})\]
OpenStudy (anonymous):
can you help me with that problem aswell ?
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OpenStudy (anonymous):
i got \[24x ^{2}\sqrt{3}\]
OpenStudy (amistre64):
multiplication doesnt care in what order you do it...\[2x(3) *\sqrt{12x}*\sqrt{4x} = 6x \sqrt{48x^2}\]
OpenStudy (anonymous):
cant i simplify that further ?
OpenStudy (amistre64):
6x 4x sqrt(3)
24x^2 sqrt(3)
OpenStudy (anonymous):
same as my answer ?
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OpenStudy (amistre64):
you were right :)
OpenStudy (anonymous):
thank youuu :) i had to double check ! :D
how about this one : \[\sqrt{2x ^{2}} \sqrt{10x ^{6}}\]
OpenStudy (anonymous):
i got \[2x ^{4} \sqrt{5}\]
OpenStudy (radar):
You seem to have the hang of it!
OpenStudy (anonymous):
so its right ? :)
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OpenStudy (radar):
It is the same as what I got. So I think it is right.
OpenStudy (anonymous):
and its the same steps for addition ? for example \[4^{3}\sqrt{a} + ^{3}\sqrt{64a}\]
OpenStudy (anonymous):
i got \[16^{3}\sqrt{a}\]
OpenStudy (anonymous):
but im not sureee
OpenStudy (radar):
Is that 4 cuberoot of a + cube root of 64a? If it is\[4\sqrt[3]{a}+\sqrt[3]{64a}=8\sqrt[3]{a}\]
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OpenStudy (anonymous):
yes it is , your right . i got confused with it
OpenStudy (radar):
You're doing fine, I've got to run. good luck
OpenStudy (anonymous):
thank youuuu ! :)