Question

how do you simplify

2a^2+5a-3??

Answer 1

may be it means to put it into its counterpart... y = M(x-h)^2 +k ?

Answer 2

well the whole equation is

16a^4-1/2a^2+5a-3 * 2a^2+9a+9/4a^2+1

Answer 3

You have to factor it: \[2a^2+5a-3\]
You get \[(2a^2)(-a-3)\]
Then: \[2a(a+3) -1(a+3)\]
Finally: \[(2a-1)(a+3)\]

Answer 4

\[\frac{16x^4 -1}{2a^2 +5a -3} * \frac{2a^2 +9a +9}{4a^2 +1}\]

Answer 5

you people are a bit confusing- i mean that you're making it more complicated

Answer 6

Yeah, amistre, that's totally irrelevant. It's a quadratic equation; all you have to do is factor it.

Answer 7

so far I have

(4a^2+1)(2a+1)(2a-1)/(2a+?) * (2a+9)(a+1)/(4a^2+a)

Answer 8

lol....well it helps to know what the actual question is :)

Answer 9

how do YOU simplify 2x^2 +5a -3 ?? lol

Answer 10

yeah lol that was my question

Answer 11

yes, but not is you're making it more complicated
you;re just adding mroe steps

Answer 12

She/he asked for \[2a2+5a−3\] to be simplified. That means factoring it into binomials.

Answer 13

she

Answer 14

i didnt add any steps... I simply was wondering what it was talking about to begin with. right?

Answer 15

\[2a^2+5a−3\] should be the equation; my bad.

Answer 16

I just need that to be factored so I can simplify the rest of the problem

Answer 17

Please read the steps that I posted previously, and tell me if it helps at all.

Answer 18

not really. It only makes it more confusing.

Answer 19

in the context of the rest of the "question", then yes; factoring it is appropriate.

Answer 20

i dont see it factoring to anything useful; so factor the difference of cubes and leave that part alone ;)

Answer 21

Ok thanks :D

Answer 22

you get square roots involved if you factor that thing there, and the other one is clean of them....so they dont cancel anyways... make sense?

Answer 23

A little more than it did. This is what I got:


(2a-1)(2a+1)(2a+9)(a+1)/2a^2+5a-3

Answer 24

without doing the math myself, that looks about right :)

Answer 25

Awesome lol thank you

Answer 26

x = -5/4 +- 7/4

x = 12/4 = 3

x = -2/4 = -1/2

(2x-1)(x+3) .... or this :)

Answer 27

(x+6/2)(x-1/2)

(x+3)(2x-1) is right... now that I have a moment to see it correctly ;)

Answer 28

That's what I thought it was. Except I had the signs switched.

Answer 29

(2a-1)(2a+1)(2a+9)(a+1)
---------------------
(2a-1)(a+3)

Answer 30

2a^2 +9a +9

(a+6/2)(a+3/2)

(a+3)(2a+3) is what I get on the top over there

Answer 31

so the answer would be:
\[(2a+1)(2a+9)(a+1)\div (a+3)\]

Answer 32

(a+3)(2a+3) (4x^2+1) (4x^2-1)
----------- ----------------
(2a-1)(a+3) (4x^2+1)



(2a+3) (4a^2-1)
---------------
(2a-1)


(2a+3) (2a-1)(2a+1)
---------------
(2a-1)


(2a+3)(2a+1)

Answer 33

how did you get a+3 on the top?

Answer 34

4a^2 +8a +3 is what I get if I did it right ;)

(a+3)(2a+3) = 2a^2 +9a +9

Answer 35

(a+6/2)(a+3/2)

(a+3) (a+3/2)

(a+3)(2a+3)

Answer 36

but when you factor it back to 2a^2+9a+9...the 3's don't add up to 9

Answer 37

2aa + 3a +2(3)a + 9

2a^2 +3a +6a +9

2a^2 +9a +9

Answer 38

Ooooh ok I think I got

Answer 39

am I right :)

Answer 40

Yup!! Thanks! Now I have 4 more to go....jeez

Answer 41

lol good luck ;)

Answer 42

thanks