Question

rationalize: 10/ 1+3i

Answer 1

1- 3i ?

Answer 2

You need to multiply both the numerator and the denominator by the conjugate of \[1+3i\]
So do: \[(10/(1+3i))((1-3i)/(1-3i))\]
That should get rid of any imaginary numbers.

Answer 3

so my answer would result to 1-3i right?

Answer 4

(10/ 1+3i) *(10/ 1-3i )
(10-30i)/(1-9i^2)
(10-30i)/(1-9(-1))
(10-30i)/10
1-3i

Answer 5

Yes, that's the right answer.

Answer 6

thank you ! i had to double check :)