Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Let f be a function of two variables and suppose that all the first order partial derivatives of f exist and are continuous at all points. Show that for the composite function w=xyf(xz,yz) the following equation holds: x(dw/dx)+y(dw/dy)-z(dw/dz) = 2w

OpenStudy (anonymous):

are u comparing the derivative form? for example of w in comparison to x? before i answer the question, because there are many ways to do this, are u in high school or calc 1 university?

OpenStudy (anonymous):

Cal 3 university. This is a partial derivatives question

OpenStudy (anonymous):

kk, give me min to type it out.

OpenStudy (anonymous):

i just finished calc 3, had my exam yesterday haha

OpenStudy (anonymous):

Really? Mine is tomorrow at 9am

OpenStudy (anonymous):

good luck!!!! mine was pretty tough!

OpenStudy (anonymous):

I'm expecting it to be difficult. I understand most of the vector geometry stuff. Its the Taylor series stuff and implicit partial differentiation that is getting me.

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

this is a one slide ppt on partial derivatives that might help u that my prof posted up.

OpenStudy (anonymous):

see if that helps, cuz it would be extremily long to write out the proof.

OpenStudy (anonymous):

I'll give it a shot. Thanks.

OpenStudy (anonymous):

if it doesnt work let me know we'll work it out here.

OpenStudy (anonymous):

hey js lets chat

OpenStudy (anonymous):

we should get lik a really big chat group..... luv that song

OpenStudy (anonymous):

kk luv that

OpenStudy (anonymous):

hey js chat with us

OpenStudy (anonymous):

why dont u just chat in the group chat instead of in the problem chats?

OpenStudy (anonymous):

idk but we could do it that way 2

OpenStudy (anonymous):

Got it sorted. Thanks!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!