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Find the indefinite integral. 6x^5/(x^6+4x)^2 There is an integral sign in front of the equation i just could not add it
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[S] works for an integral sign
if we substitute u = x^6 +4x; du = 6x^5 + 4 dx
it is actually 6x^5 +4 / (x^6+4x)^2
well thats helpful ;)
then we end up with a substitution that is: [S] 1/(u^2) du [S] u^(-2) du which is doable right?
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do you see hoe that happens?
rite. okay so then u would get -1/x^6+4x
plus the constant
yes :)
thnxs
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youre welcome :)
pshhhh...
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