if f(x)=3x^2-2x-5, find(2u+1) can you explain how to work the problem and whats the answer
i can get to f(2u+1)=3(2u+1) after that i don't know

Question

radar · Answer

$$f(2u+1)=3(2u+1)^{2}-2(2u+1)-5$$
Thats a start.

radar · Answer

$$=3(4u ^{2}+4u+1)-4u-2-5$$ just keep on trucking!

radar · Answer

Earth to shrryflores, do you follow so far?

anonymous · Answer

yes

radar · Answer

Let's continue then:
$$12u ^{2}+12u+3-4u-7$$
$$12u ^{2}+8u+4$$

radar · Answer

change that +4 to -4

anonymous · Answer

ok it makes since

radar · Answer

since there was no = sign I think that is as far as needed$$12u ^{2}+12u-4$$

radar · Answer

$$f(2u+1)=12u ^{2}+12u-4$$

anonymous · Answer

$$f(2u+1)=12u^2+8u-4$$
You can find the roots of u using the quadratic formula:
$$u=-\frac{1}{3}\pm \frac{2}{3}\rightarrow u=-1, u=\frac{1}{3}$$

radar · Answer

I was wondering if it was to be taken any further?  Couldn't determine if they were wanting the roots.

anonymous · Answer

I gave the roots just in case

radar · Answer

Fine business,  they say "whats the answer" maybe that was what they wanted.  thanks and good luck to you and shrryflores