Question

is there a value for h that makes it possible for the equation √(x+h)+5=0 to have any real number solution? explain

Answer 1

is x+h+5 all under the square root? or just x+h?

Answer 2

just x+h

Answer 3

ok.. so you want to find a value for h that makes the expression
\[\sqrt{x+h}+5=0 \implies \sqrt{x+h}=-5\]
but the square root can't have a negative value. so, such h doesn't exist.

Answer 4

wait, the sqroot of a number can have a negative value, the SQUARE of a number can't have a real value

Answer 5

square both sides and you get x+h = 25

Answer 6

that's not right mindedone, you're suggesting that h=25-x is a solution.. check by plugging back into the equation and see what you get.

Answer 7

Keep in mind though that if you plug h=25-x into the original equation you get +-sqrt(25) = -5, and so the negative square root does satisfy the equation.

Answer 8

you get sqrt(25) = -5

Answer 9

sqrt(25) = +-5