Determine whether each curve for y=4x^2 is symmetric with respect to the x-axis, the y-axis and the origin.
So, what have you tried so far?
It's actually making alot of sense. So far, all my answers are correct in the back of the book, so now I want to make sure i'm getting the others right. I didn't understand the entire concept until now so its coming together quite well thanks to you. I'm going to submit in here what I have so far, so maybe you could tell me if it looks right if you would be so kind.
y=4x^2 To solve for the x-axis, I have -y=4x^2 I cannot do anything else with this equation and since it is not the original equation, I am saying there is no x-axis symmetry.
To solve for y-axis, I have y=(-4x) (-4x) y=4x^2 Original Equation makes it y-axis symmetric
To solve the origin (replacing with-x, y), I have y=(-4x) (-4x) y=4x^2 Origin YES........ I sure hope i'm doing this a bit better...what do you think?
yes you right
Really? That is awesome. I sure have been studying hard considering this isn't even my work. I passed Algebra in 2002 in college with a 100%; however apparently after all those years you forget alot. Its pretty neat though.
yes its true but when you learned something and forget through some time you remember this very fast
Im not so sure that I got the origin right though. Aren't I replacing x,y with (-x,-y)
no let's see for example y=x^3 x-axis is -y=x^3 y-axis is y=(-x)^3
So original equation is y=4x^2 For the origin, shouldn't I be replacing the x,y with (-x, -y)? Making it: -y=(-4x) (-4x) -y=4x^2 Making the origin not symmetric right?
what don't you understand
y-axis for y=4x^2 is origin function
Okay, so correct the first time. Ugh.
I put that on my calculator as well and got what you got as well. Thank you very much again.
Okay, so correct the first time. Ugh.
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