Question

CAL 2:Find indefinite integral using simple substitution: Integral of (cosx/(1+(sinx)^2))dx

Answer 1

\[\int\limits cosx/(1+(sinx)^2)dx\]

Answer 2

yes
u=sin(x)
du=cos(x)

Answer 3

\[\int\limits_{?}^{?}1/(u ^{2}+1)du\]

Answer 4

it is arctan(u)

Answer 5

and u = sin(x)

Answer 6

don't forgot constant )))

Answer 7

full answer is arctan(sin(x))+const

Answer 8

that simple? should I use first as denominator to change to 1+sin^2x and use identity?

Answer 9

as sin^2x=1-cos^2x

Answer 10

no

Answer 11

lululz this aint sinh and cosh

Answer 12

its called partly integration

Answer 13

sorry it was not arctan it must be cotan

Answer 14

right answer is cot(sin(x))+const

Answer 15

ok I was thinking:\[\int\limits cosx/1+(1-\cos^2x) \to change given and than go from there but I see, \it would be more complicated\]

Answer 16

no don't this

Answer 17

its not cot it can't be I think inverse tan was right

Answer 18

no its cot=tan^-1

Answer 19

thank you

Answer 20

julia, where are you from?

Answer 21

if not secret =)

Answer 22

:O) Miami

Answer 23

and where do you study?