Question

How do I find the second derivative of -1/sin ^2x ?

Answer 1

is it -1/sin^2 (x)

Answer 2

yes

Answer 3

i mean sin square x right?

Answer 4

write 1 as sin^2x+cos^2x

Answer 5

it will become-(1+cot^2x)

Answer 6

u need help?

Answer 7

actually i was not able to post it on grp chat

Answer 8

@zain

Answer 9

I'd just change it to -csc^2(x) and then take the first derivative, and then chain rule for the second derivative

Answer 10

or else use uv rule

Answer 11

Thanks guys

Answer 12

taking 1=u & sinx =v & integrate

Answer 13

im sry...differentiate , (not integrate)

Answer 14

Differentiate by parts!! lol :)