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Mathematics 16 Online
OpenStudy (anonymous):

Hello, I need help with an equation i did it, but it looks like it needs revision • A teacher is looking for the best option in purchasing school supplies for a classroom. Company A is offering a discount for every dollar amount spent; Company B is offering a higher discount than Company A, but the discount is applicable only for every dollar amount spent above $20. Determine which company will offer a better price based upon the dollar amount the teacher spends on school supplies.

OpenStudy (anonymous):

do you have a formula for determining the cost of each company? If you don't, develop a formula for each company, and then I can help you from there

OpenStudy (anonymous):

yes i do there are three separate formulas y=0.8x y=0.7x+6 and y=x

OpenStudy (anonymous):

I am having trouble with the excel graph, and i don't know if something is just not adding up

OpenStudy (anonymous):

I'm not sure what those equations correspond to

OpenStudy (anonymous):

well, the discounts are 20% from Company A based on any amount purchased, and 30% from Company B for supplies purchased above $20.

OpenStudy (anonymous):

ok, so when for the second one, when x is 20, y is twenty, and afterwards y = (x -20) * .7

OpenStudy (anonymous):

sorry, y = (x - 20) * .7 + 20

OpenStudy (anonymous):

yes but how do I put it in a graph? how do I find my points for those 3 equations? I attached an excel graph, but something isn't accurate

OpenStudy (anonymous):

sorry, i can't open up the excel graph. but to solve the problem, you solve for the two equations i posted above

OpenStudy (anonymous):

did you use scatter plot instead of line graph?

OpenStudy (anonymous):

go to where you change chart type, and choose the segmented line, instead of the smooth curve under scatter plot

OpenStudy (anonymous):

in the scatter chart?

OpenStudy (anonymous):

Can I put any numbers to solve the equation, or how would I solve this equations above?

OpenStudy (anonymous):

you see how two of the equations intersect on the graph?

OpenStudy (anonymous):

yes, at 60, but at the bottom, i have a bump

OpenStudy (anonymous):

these are the points that I use, 0, 20,40, 60,80

OpenStudy (anonymous):

at x = 20, it will be discontinuous. it's supposed to be

OpenStudy (anonymous):

x1 y1 x2 y2 0 0 0 0 20 16 20 20 40 32 30 27 60 48 40 34 80 64 60 48

OpenStudy (anonymous):

i think something is wrong with the points that I'm using

OpenStudy (anonymous):

use the equations i gave then

OpenStudy (anonymous):

Are they the same as y=0.8x and 0.7x+6? Or can you regive me your equations if they are different?

OpenStudy (anonymous):

why is it six and not 34? from 0 - 20, the equations should be y = .8 * x and y = x, after 20, it should be y = .8 x and y = .7 * x + 34

OpenStudy (anonymous):

you know what, nevermind, the equation is right, i added 14 + 20 instead of subtracted

OpenStudy (anonymous):

so your equations are correct

OpenStudy (anonymous):

Whew, a relief since I have been working on them since yesterday. But my question is, what points do I use to plot the graph? How do I solve the equations?

OpenStudy (anonymous):

I'm like math illiterate, which is probably why you're wondering why I'm having a hard time with these equations.

OpenStudy (anonymous):

your points are correct, it shows exactly where the two graphs are equal. the only problem is, you chose to have the graph smooth the lines, instead of jagged. make them jagged

OpenStudy (anonymous):

you see where it's curvy? it should just be an angle

OpenStudy (anonymous):

how do I make them jagged? and do I need to do a point for the equation y=x

OpenStudy (anonymous):

no, read up top, you need to change the graph type

OpenStudy (anonymous):

look in excel where it has the types, where one is curved, and the other is jaggedy

OpenStudy (anonymous):

So you can see my graph in front of you, does it make sense to you with both companies?

OpenStudy (anonymous):

yes, it's fine, except that it's curved, and not jaggedy

OpenStudy (anonymous):

in my excel, if i right click on the graph, and go to CHANGE CHART TYPE, i have the option on the bottom of the window to change it to a jagged scatter plot. other than that, it's supposed to have them cross like that, and the one is supposed to slightly change direction

OpenStudy (anonymous):

Ok and how do I simultaneously solve those 3 equations?

OpenStudy (anonymous):

you don't simultaneously solve all three

OpenStudy (anonymous):

only the two, after x > 20

OpenStudy (anonymous):

ok and how do I solve those 2? I'm sorry if I sound clueless, but I just don't understand math

OpenStudy (anonymous):

you see how you have them already solved for y? you just set the right side of the one to the right side of the other, as in .8x = .7x+6, and solve for x

OpenStudy (anonymous):

ok let me try that

OpenStudy (anonymous):

x=60?

OpenStudy (anonymous):

Would I be able to attach the file for the word problem so you can see if I did it right?

OpenStudy (anonymous):

no, you did that right, but your answer doesn't match your data

OpenStudy (anonymous):

so how do I fix it?

OpenStudy (anonymous):

wait, is that your x or your y? your x is 60, and your y is 48?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

then you're done

OpenStudy (anonymous):

So the equations with the graph are accurate?

OpenStudy (anonymous):

This is what it asks for?

OpenStudy (anonymous):

3. Solve the system of linear equations algebraically using either the substitution method or the elimination method to determine where the two cost options are equivalent, showing all work. a. Explain each step used to solve the system of linear equations. Include the following in your explanation: • The algebraic method used to solve the system of equations • All mathematical operations used to solve the system of equations • The solution of the system of equations

OpenStudy (anonymous):

Which method did I use?

OpenStudy (anonymous):

substitution

OpenStudy (anonymous):

How did you come up with all three equations?

OpenStudy (anonymous):

Are you there?

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