Question

use the ratio test to determine if series is convergent for sigma 1 to infinity (n!)^2/(2n)!

Answer 1

An = (n!)^2/(2n)!
An+1 = ((n+1)!)^2/(2n+1)!
and then abs (An+1/An)

Answer 2

hi im still confused

Answer 3

which part?

Answer 4

i solved the problem and my final answer is n+1/2 and im not getting the right answer

Answer 5

do you know how 2(n+1)! becomes( 2n+1)(2n+2)

Answer 6

n! = n (n-1)(n-2)...1
(2n!) = 2(n!) = 2(n(n-1)(n-2)...1)
(n+1)!= n+1((n+1)-1)(n+1)-2)...1)
like that