Question

quick clarification on quadratic equation

Answer 1

\[-16y ^{2}=24y+9\] my ? is, would a=-16, b=24, and c=9?

Answer 2

or is it scrambled up so it's not in order?

Answer 3

it can

Answer 4

I mean no thats wrong

Answer 5

Before doing quadratic equations, you always have to set them equal to zero. So you would have to add 16y^2 to the other side.

Answer 6

i just need to know what a b and c are

Answer 7

So your a is positive 16.

Answer 8

Your b and c stay the same.

Answer 9

\[ay^2+cy +c =0\]

Answer 10

so you have to set up your equation to zero you can set however you want it as long as it equals zero.

Answer 11

ok thanks. Now I need to solve it. Will I have 2 non real answers?

Answer 12

woops i got it wrong \[ay^2 + by + c = 0\]

Answer 13

nope you should get two real numbers.

Answer 14

ok thanks. I'm gonna try and work it out. can someone let me know if this is right once I get it

Answer 15

most definitley

Answer 16

definitely **

Answer 17

\[-24+ or - \sqrt{576-576}\over -32\] I got to this step and I'm assuming the 576 cancels, but idk exactly what to do with the other numbers?

Answer 18

Yes, they cancel, and the square root of 0 is 0.
So for +:
-24+0=-24. Then divide it by -32, to get .75 or 3/4.
And for -:
-24-0=-24. Then divide it by -32 to get .75, or 3/4.

Answer 19

Hold up, caught an error. When you get your final equation, you divide it by 2a. Look at your last post. You divided by -32. Our a=16. Not negative 16. So 2a= positive 32.

Answer 20

ok thanks for catching that. I'm wondering how I should type the 2 answers. it's an online assignment and it's picky with the correct format, so what exactly would it look like?

Answer 21

is is -24+ 3 over 4, and -24 - 3 over 4?

Answer 22

neither..

Answer 23

and my other ? is if there is a square root involved in the answer at all? or if that cancled out completely? Thanks for your help

Answer 24

drats.. I guess i'm not sure what my answer should look like exactly

Answer 25

This particular equation has only one answer, 3/4, because the square root turns out to be 0. If they are picky, you could write that the two final steps were (-24+0)/32, and (-24-0)/32, but because we are dealing with zeroes, they both have the same answer.

Answer 26

someone else said there would be 2 solutions, and i think because it was squared it is supposed to have 2. Thanks, i'll try that

Answer 27

no square root sign i supose?

Answer 28

it wont let me do the 0 over a fraction. hm

Answer 29

Yes, typically this equation would have two answers, because before every square root symbol is a "plus-or-minus" \[\pm\] sign. In this case, under the radical is zero. So there is only one solution.

Answer 30

you were right. I typed it in wrong though. Thanks so much! I have another one that i am not sure how to finish it off. Would you mind helping me with this one? Or should I post the question for someone else? :)