Cylinder with cone
removed

Question

anonymous · Answer

attachment

amistre64 · Answer

you want the volume left after cone is removed?

amistre64 · Answer

Vcylinder = Base area x height

Vcone = (1/3) Vcyl

Vleft over = 2/3 Vcyl

anonymous · Answer

i need that vcylinder-vcone

amistre64 · Answer

Base area = pi r^2 = 36pi

Vleft = 2(12)pi = 24pi

amistre64 · Answer

thats wrong, i missed a step lol

amistre64 · Answer

(16)24pi = 384pi

(2)384pi
-------  = 256pi = about 803.84
    3

amistre64 · Answer

i see my mistake again lol

anonymous · Answer

so i have to subtract 384 and 256

amistre64 · Answer

1 - 1/3 = 2/3...... let me redo that, I used a wrong number.

amistre64 · Answer

Base area = pi r^2 = 36pi

16(36pi) = 576pi  is the area of the cylinder

(2)576pi
-------  = 384pi  =about 1205.76
     3

anonymous · Answer

then subtract it right

amistre64 · Answer

576pi is the volume of the container;  the volume of the cone is just a third so what we have left over is 2 thirds of the volume when the cone is removed.

whats left is 384pi , which is about 1205.76  and that is the answer.

No subtracting nothing from anything :)

anonymous · Answer

umm ok thank and can u help me with the other problem

amistre64 · Answer

which one...

anonymous · Answer

find the title that said cone