Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

I need someone to just check my work... and tell me where I went wrong?

OpenStudy (anonymous):

The problem is 2^x+3=5x

OpenStudy (anonymous):

What did you get?

OpenStudy (anonymous):

next step: (x+3)ln2/xln2=xln5/xln2

OpenStudy (anonymous):

I got 2.269

OpenStudy (anonymous):

next step: x+3/x=ln5/ln2

OpenStudy (anonymous):

next step: x+3/x=2.322/1

OpenStudy (anonymous):

Something is wrong. Was the original equation \[2^{x+3} = 5^x\] ?

OpenStudy (anonymous):

no 2^ x+3=5x

OpenStudy (anonymous):

Ok, then when you take the ln of both sides you'll have ln5 + lnx on the right hand side of the equal.

OpenStudy (anonymous):

Which is gonna be a pain.

OpenStudy (anonymous):

Was it \[2^{x+3} = 5x\] ?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Yeah, there's no good way to simplify that. I suspect you have the question wrong.

OpenStudy (anonymous):

Best you can do is something like \[x(ln 2) - lnx = ln(5/3)\]

OpenStudy (anonymous):

Err wait, that should be ln(5/8) on the right side.

OpenStudy (anonymous):

My teacher told us to set each side to the natural... which gave me: (x+3)ln2=xln5

OpenStudy (anonymous):

Then I needed to get everything canceled out by cross multiplying... so I divided both sides by xln2

OpenStudy (anonymous):

That's not right though. Unless you had 5^x on the right side originally.

OpenStudy (anonymous):

Was it \(5x\) or \(5^x\)

OpenStudy (anonymous):

the second one... I just looked in my book. Im so sorry

OpenStudy (anonymous):

Ok good.

OpenStudy (anonymous):

So yeah that's right. take the ln of both sides (or any log really)

OpenStudy (anonymous):

Then solve for x. Don't plug anything into your calculator until you have something where x = something that has no x

OpenStudy (anonymous):

(x+3)ln2=xln5 is correct for starting out

OpenStudy (anonymous):

ok... then what do I need to divide both sides by? she taught us to cross multiply? I divided both sides by xln2 just to cancel out. And I ended up with x+3/x=ln5/ln2

OpenStudy (anonymous):

Get all terms with an x on one side.

OpenStudy (anonymous):

Or that. Cross multiplying works fine

OpenStudy (anonymous):

I usually multiply out products, but you don't need to here

OpenStudy (anonymous):

Just be sure that you do (x+3)/x = ln5/ln2

OpenStudy (anonymous):

Not just the 3.

OpenStudy (anonymous):

I did and I got: x+3/x= 2.322/1

OpenStudy (anonymous):

then: x+3=2.322x

OpenStudy (anonymous):

Don't plug things in.

OpenStudy (anonymous):

Keep solving the equation until you have x by itself. x = something that has no x.

OpenStudy (anonymous):

Then plug in

OpenStudy (anonymous):

Im not sure what/where.I am attempting to get x by itself? I thought that is what I was doing?

OpenStudy (anonymous):

I think cross multiplying is just making this harder.

OpenStudy (anonymous):

I just got a different answer of -4.425

OpenStudy (anonymous):

Lets back up.

OpenStudy (anonymous):

Ok..Im just trying to follow the instructions. But Im willing to try anything at this point

OpenStudy (anonymous):

\[(x+3)ln2=xln5\] \[x(ln2)+3(ln2)=x(ln5)\] \[x(ln2)- x(ln5)= - 3(ln2)\] \[x[(ln2)- (ln5)]= - 3(ln2)\] \[x= \frac{- 3(ln2)}{(ln2)- (ln5)}\]

OpenStudy (anonymous):

Thanks for your time.. I appreciate it. I will continue to search for the answer. I need to learn it the way she taught us, Im afraid I will be jumping the gun and not learning anything... thanks so much.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!