Question

clarification on the answer for this quadratic equation!

Answer 1

\[-4x ^{2}-x=-2\]

Answer 2

right now I have \[x=1+ or - \sqrt{-31}\over -8\] I don't know if there can be any more done

Answer 3

I never know when exactly the i's come into play..

Answer 4

4x^2 +x -2 = 0

-1/8 +- sqrt(33)/8 should be the answer

Answer 5

put everything on the side that makes the x^2 part positive...

Answer 6

so there are 2 non real answers?

Answer 7

0 = 4x^2 +x -2 is alot easier to play with :)

Answer 8

there are 2 real answers. why you get sqrt(-31)? thats wrong

Answer 9

sqrt(1-(4)(4)(-2)) = sqrt(33)

Answer 10

1-32 is how I got that.. 4 times a times c is what my format told me to do.. hmm. must have messed something up

Answer 11

get your quad to be a positive 4x^2..... you can put that stuff on either side of the equals sign to make life easier.

Answer 12

sqrt(1 -(4)(4)(-2)) = sqrt(1 + 32) = sqrt(33)

Answer 13

gotcha. I see where I messed up, thanks! Would you mind helping with this one once I work out the answer, just to make sure i'm doing it right?:)

Answer 14

not a problem

Answer 15

\[X ^{2}+10X+25=0\] Is the problem.

Answer 16

so far I have \[-10 + or - \sqrt{4}\over 2\] So i'm wondering if the 2 and 4 turn into 2 over 1...?

Answer 17

if we want to really work this with the quad formula then we should get:

-10/2 +- sqrt(100 -(4)(25))/2

-10/2 +- sqrt(100-100)/2 <- thats zero

-10/2 = -5

Answer 18

ohh i did 100-96 to get that. i wrote 24 instead of 25..My bad. So is there only 1 solution for this?

Answer 19

yes, only one solution. It touches the x axis in only one place....x = -5

Answer 20

thank you!

Answer 21

youre welcome :)

Answer 22

I have like 10 more of these so i'll probably keep posting them on here to make sure I get them right. So if you don't mind I will just stay on this window and show them to you, otherwise I can see if others want to help. It's up to you! I understand if you have better things to do :)

Answer 23

better things? no, but I might not be able to get to them, so post them in the left side so others can have a chance at them :)

Answer 24

Ok sounds good! Ha, thanks for your help :)