Just would like to make sure my answer for this quadratic expression is correct!
\[x ^{2}-8x+16=0\]
(x -4)^2=0 x=4, 4
x=4
and so far I have, \[x=8 + or - \sqrt{64-64}\over 2\] I know the 64s can cancel..but what will my answer look like from here?
there are two solutions for this one 4 and 4
ohh so theres one solution? just 4
no..two
ha, sorry i keep typing after you answer my ?
every quad. has two solutions
could be real or complex
4 is 4 so you would only write it once if you were solving by factoring or quadratic formula
ok. this is an online assignment I have to submit so i'd like to get the formula right. I should just put 4 under the 1 solution?
we use the quadratic formula...when u can't factorize or it is hard to guess...but here 4 and 4 add up to 8 and gives the product 16.
there r two solutions.. 4 and 4
ok thanks.. It just seems strange putting only the 4 in as 2 different answers. They are both real solutions?
is it multiple choice
yes they are both real obviously....but dont forget to write it twice otherwise teacher might think u got only one root..
no, I select whether there are 2 different real solutions, 2 non real solutions or 1 solution
ok then ...all good
fan me if u liked my help..thanx
2 real solutions
did you enter it in
It's online so it's picky with the format. Do I have this in a root?
no i haven't yet. I will in a sec
it says two DIFFERENT solutions, I still think it is one solution even if is a quad bc 4 is distinct
i just realized it says one repeated real solution..so maybe i should put it under that category?
I think so to, i'll find out!
yes......
YES!!!!!
yep, that was correct. Sorry, my fault I didn't specify that. Thanks for your help guys!
I knew something wasn't right...you're welcome...fan me please
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