Could anyone please help me finding the general solution of an ODE? Thanks!!
(xy'-1) lnx = 2y

Question

Could anyone please help me finding the general solution of an ODE? Thanks!! 
(xy'-1) lnx = 2y

anonymous · Answer

rearranging the equation we get,
xy' -2y/lnx =1

anonymous · Answer

integrating facor= 1/ (lnx)^2

anonymous · Answer

solution will be y *I.F. = INEGRATION SIGN ( I.F.) DX +c

anonymous · Answer

ok?

anonymous · Answer

1 sec please

anonymous · Answer

Yeah thanks a lot ankur 504! I just got it following your rearrangement!!!! Thanks

anonymous · Answer

best of luck with ur maths

anonymous · Answer

Could someone tell me the steps of solving this system of differential equations? Thanks!!!

x'= x-y+z
y'= x+y-z
z'= 2x-y

anonymous · Answer

is it a partial differential problem?

anonymous · Answer

i am not sure but the hint says that one of the eigenvalues of the correcsponding matrix is r1=1.

anonymous · Answer

right hand side makes a 3 X 3 matrix.

anonymous · Answer

yes

anonymous · Answer

1 -1 1
1 1 -1
2 -1 0

anonymous · Answer

exactly!!!

anonymous · Answer

what are the steps then? I can figure the rest by myself if you don't mind giving me some directions.

anonymous · Answer

ok wait a min..

anonymous · Answer

we calculate the Jacobian?

anonymous · Answer

I gave up...I'm just a first year uni student. Sry...U better post your question on the left side...I think POLPAK can solve it

anonymous · Answer

wow that's pretty impressive. Thanks a lot though!!