How do you solve these equations they don’t show me in my book. Once I know how to solve these I can solve the others. (X-81)/(x-3) (X5+y5)/(x+y) (a3+6a2+12a+8)/ (a+2) (5a3+8a2-23a-1)/ (5a2-7a-2)
first one...(X-81)/(x-3)=0 x=81, 3
oh there was a divide sign !!!!!!! errrrrrrr
lets do it again
(x-9)(x+9)/x-3) (x-3)(x+3)(x+9) /(x-3) (x+3)(x+9)
ok now third one...
(a3+6a2+12a+8)/ (a+2) (a+2)(a2+4a+4)/(a+2) (a+2)^2
now fourth one..
I think I might have asked the question wrong because and I am confusing you. They want the answer to look something like this (x2 -6x +9)/ (x-3) = (x-3)
I've done the same too
not to doubt you but if you doing the same thing give the answer to (x2 +8x-16)/(x+4)
your question is wrong ..it should have been (x2 +8x+16)/(x+4)= (x+4)
the answer (x+4) is what I was look for
thats what I had to solve for
happy now??
noo ( again not trying to doubt your abilities) what I was checking was if your answers would look like mine. Now that I see they are what I am asking you to do is tell me the answer to the equations, because I can't see the answers your trying to give.
Do u want me to do any other ques?
sure
which one ?
I'm haveing alot of trouble with these types of questions (X5+y5)/(x+y)
okay..do u know long division method ???
yes
i feel u can get this one done by that..
I've tried but the answer keeps coming up wrong
'keeps coming' means u have tried more than once... haven't u ???
yes, but I get messed up in all the variables
i m going to do it on paper...I'll write the answer here...lets see what we going to get...
okay
x4-x3y+x2y2-xy3+y3
is that what u got?
no, so how did you get there
Oldnick, are the X and x the same variable
ahhh !!! made a lil mistake in the end...ig guess
no ...i think i was right...@radar whats ur thoughts??
@radar: yes
@ankur504: how did you get to your answer?
long division
Is this the problem as written in your text or worksheet?
@ankur504: yeah I now that give me the proses you used.
I dont know how to type that method here...sorry
\[(x ^{5}+y ^{5})/(x+y)\]
@ankur504: use the equation tool bar
wait a min..
@radar: the first variable looks wrong
do you mean it is not x^5???
Please restate the problem
look at this pic..i havent done the full problem but thats enough to give u an idea
@radar and @oldnick..what u have to say
@ankur504: I can't really see what your doing
i m exhausted...sry ...thats all I could do...my bad (
so whats our equation that we are longjohning?
\[(x+y)(x ^{4}-yx ^{3}+y ^{2}x ^{2}-y ^{3}x+y ^{4})\]
(X5+y5)/(x+y)
amistre64 we are trying to do (x^5+y^5/(x+Y)
@amistre: could you please have a look at the picture which I've uploaded top see if I m correct or not?
pic looks good, from what I can read :)
I think I put the factors up there the (x+y) would cancel and leave the (x^4..............y^4)
x^4 -x^3 y --------------------- x+y | x^5 + y^5 -x^5 -x^4 y --------------- -x^4 y +y^5 +x^4y +x^3 y^2 ----------------- +x^3 y^2 +y^5 and it keeps going till you get no x values to plug into it
@amistre64: I can't understand what you did there.
its just long division.... the same way you do numbers....but with xs and ys
les try 27/5 we want a number that is less than but close to 5*x = 27 lets use 5 5. <- when we multiply this to the 5 we "subtract" it from the 27 ------ 5 | 27.00000 - 25 <- 5*5 = 25....but!! 27-25 is what we want for an answer ----- 20 <- this is whats left over and drop down the next "number"
oldnick, i suggest you factor the (x^5+y^5) first using the rule \[x ^{n}+y ^{n}\] when n is odd. n is 5 so it is odd.
thats the problem is that the book gives an example on how to do the equation with (x3 +1)/(x+1). but not with only variables, so I don't now what to do with variables and large numbers.
5.4 ------ 5 | 27.00000 - 25 ----- 20 <- now we want a number that is 5*x = 20, use 4 :) -20 <- 5*4 = 20...but!! we want 20 - 20 for an answer.. ------- 0
@radar: whats the xn+yn rule
the variables that cancel go away...and you add the ones that are alike and bring down the ones that arent....
\[(x+y)(x ^{n-1)}-yx ^{n-2}+a ^{2}x ^{n-3}-...+y ^{n-1})\] you can use this then as you see the x+y divides into the x=y giving 1 and you have the long one left which is the answer4
(x) * ? is close to x^5. lets use x^4 (x+y)x^4 = x^5 + x^4 y so we subtract that to get a new round -(x^5 +x^4 y) = -x^5 -x^4 y x^4 --------------------- x+y | x^5 + y^5 -x^5 -x^4 y <- we subtract it --------------- 0 -x^4 y +y^5 <- the x^5 goes to zero and the only things left that didnt subtract to zero is brought down and worked again
Corrections; change a to a y. remember in this case n=5
(x) * ? is close to -x^4 y. lets use -x^3 y (x+y)-x^3 y = -x^4 y -x^3 y^2 so we subtract that to get a new round -(-x^4 y -x^3 y^2) = x^4 y +x^3 y^2 x^4 -x^3 y --------------------- x+y | x^5 + y^5 -x^5 -x^4 y --------------- -x^4 y +y^5 x^4 y +x^3 y^2 <- subtract it ----------------- 0 + x^3 y^2 +y^5 <-whats left that didnt subtract to zero is brought down and worked again
thats the easiest way I know to explain it...
on a keyboard that is :)
The keyboard does provide limitation
I'm not sure if this will help but this is what they want me to do.
and that is exactly what I showed you ;)
Then the amistre64 method (long division) is the way to go
heres the problem what you showed me I can't understand
x^5 + y^5 is the same as: x^5 +0x^4y +0x^3 y^2+0x^2 y^3+0x y^4+y^5 if you expand it out...
right I understand that
that is just impractical on the keyboard to try to use...
so instead of using all those 0 place holders... ignore them.
add together your like terms...and drop the rest down
okay
but there are no like terms
x^5 +0x^4 y + ............+ y^5 -x^5 -x^4 y --------------- -x^4 y + ............. +y^5 right?
thats where you loss me
I just included the "like term" for you to see that its just a place holder
The sum of equal powers can be factored. different rules for even vs odd powers. Not really different rules, just different patterns.
y^5 -x^4 y ------- -x^4 y + y^5 thats all there is to it....
whatever doesn subtract from each other...carries on down ....... do you see that?
like terms dont combine...so both terms drop down as they are..
what do the ------ stand for?
unlike terms dont combine is what it should read... my fingers got lazy on me :)
thats an equals bar underneath the terms to be added. 4 +5 ---- 9
we can add across like this: 4+5 = 9 or we can add up and down like this: 4 +5 ---- 9
when we do long division; we add/subtract in the vertical way.... keeps everything tidy
yes?no? makes sense? doesnt? i need to hear from you...
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