Question

Find the integral:

Answer 1

\[\sqrt{x} + 1/ x^4 dx\]

Answer 2

what is the integral of sqrt x

Answer 3

that also is
\[(x)^{1/2} + (x)^{-4}\]

Answer 4

You can rewrite that integral as the integral of (x^(1/2) + x^(-4))
Using the power rule, we get:

(x^(3/2) / (3/2)) + (x^(-3) / -3)
which may be rewritten as
(2/3) x^(3/2) - 3/x^3

Answer 5

just integrate each part individually then add together

Answer 6

add 1 to the exponents and w/e you get multiply each part by it's inverse

Answer 7

you can't add them. If he could then he would do it before the integration

Answer 8

integral of sqrt x = [2x^(3/2)]/3
integral of 1/x^4= -1/3x^3

Then add together and you get (2 x^(9/2)-1)/(3 x^3)+ C