can somebody help me solving this problems?
http://tinyurl.com/3wne3vx

Question

anonymous · Answer

this is a vector problem

anonymous · Answer

It's late where I am so I'm gonna hit some easy ones here.
(b(i)):
p dot q = ||p|| ||q|| cos(theta), where theta is the angle between the vectors.  so just multiply all that you're given, and you'll get $$ 2 \pi $$

Hope I helped with something

anonymous · Answer

can you help me with a(iii) and b

anonymous · Answer

I already gave you a hint. can you not see the answer to a (iii)?

anonymous · Answer

no

anonymous · Answer

DEC and similar to AEF

anonymous · Answer

and AF and DC are corresponding parts, but DC = AB

anonymous · Answer

AF=kDC => AF/DC = k

anonymous · Answer

and EF/DF = 1/lambda, so by the property of similar triangles...

anonymous · Answer

i get it now, how about part b?

anonymous · Answer

i dont understand part b

anonymous · Answer

i need help to find k

anonymous · Answer

kAB = AF and AF = proj FD on FA so proj FD is FD (dot) FA / |FA|^2 * FA

anonymous · Answer

i dont understand it

anonymous · Answer

is there another way to solve for k?

anonymous · Answer

yeah sorry ignore that. I miss read the diagram

anonymous · Answer

i found that DF = kp-q

anonymous · Answer

rinspd how you up load the picture?

anonymous · Answer

i used flick to upload the picture

anonymous · Answer

do you have to paid monthly?

anonymous · Answer

no its free

anonymous · Answer

do you have a link my mail it yahoo

anonymous · Answer

yeah

anonymous · Answer

I have a problem to upload picture