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Find the angle between the vectors u and v if u = (1, 2) and v = (- 4, - 2). Round answer to two decimal places. A.141.20o B.141.89o C. 143.13o D. 144.09o E. 144.54o
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use scalarproduct and acos
ok well I don't know what scalarproduct is but I have cosθ=u.v/IIuII IIvII
yes, that u.v is the scalarproduct.
the angle between vector is cool....
u.v ---- |u||v|
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<1,2> . <-4,-2> = -4 + -4 = -8 ------------------------- --- sqrt(5) sqrt(20) = sqrt(100) = 10 cos(t) = -4/5
t = cos^-1(-4/5)
t = 143.13
ive been reading about vectors allll week ;)
and that is the extent of my knowledge so far lol
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Thank you this actually make's sense too... I was missing the t=cos^-1(-4/5)
your welcome ;)
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