Question

Expand: (x+3) to the power of 3?

Answer 1

1331

Answer 2

x^3 +3x^2(3) +3x(3^2) + 3^3

Answer 3

x^3 +9x^2 +27x +27

Answer 4

Start off on the basic.

(x+3)(x+3) = x^2 + 6x + 9

Then multiply through again.

(x^2 + 6x + 9)(x + 3)

x^3 + 6x^2 + 9x + 3x^2 + 18x + 27

x^3 + 9x^2 + 27x + 27

Answer 5

i think its part of the binomial theorum; which has the coefficients of Pascals triangle.

At ^3 we get coefs of 1,3,3,1

Answer 6

then just input the first and last terms

last term decreases by ^1 and first term increases by^1

Answer 7

(x+3)^5

1 5 10 10 5 1

1x^5 +5x^4 +10x^3 +10x^2 +5x +1

1x^5 +5x^4(3) +10x^3(x^2) +10x^2(3^3) +5x(3^4) +1(3^5)

Answer 8

x^5 +15x^4 +90x^3 +270x^2 +405x +3^5 lol

Answer 9

They'll come a point when the power is too high for you to continue your precious triangle. Or too non-positive-integery

Answer 10

yeah, but its fun while it lasts :) my son thinks its cool lol

Answer 11

i'm lost... do you basically foil 3 times or what?

Answer 12

yes, "FOIL" 3 times, but that last "FOIL" becomes more of a "FOIOIOL" or some such nonesense...

Answer 13

distribute 3 times is a better acounting for it

Answer 14

I tell my kids, no you dont "FOIL" anything. You work it out thru the distributive property. And once you know what is going on....name it whatever you want :)

Answer 15

what would the final answer come out to ?

Answer 16

its already been posted..... scroll up :)

Answer 17

or... distribute it out 3 times....

Answer 18

tell me the answer again... i dont know which one the answer is?? pleaz write it again