Question

I have a hyperbola on a graph. all i know is the center and the two verticies. How do i find the equaton of it?

Answer 1

the hyperbola opens to the side like this:
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Answer 2

There's more about this at http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx

Answer 3

the true problem is that i dont have a or b or the asymptotes

Answer 4

I believe a and b can be found based on the center and the vertices, no?

Answer 5

thats what im not sure on. i know it has something to do with h and k and the vertices but im not sure how to use the verticies to get and b

Answer 6

*a and b

Answer 7

Ah, pwned. B is the problem.

Answer 8

yes

Answer 9

the verticies are (-15,9.5) and (-14,9.5) and the center is (-14.5,9.5)

Answer 10

Hm. Can I see the graph? If you can take a picture/scan it, you can upload it here using the attach file button.

Answer 11

alright

Answer 12

Also, what class is this for?

Answer 13

with the new math system its accel math 2

Answer 14

conics

Answer 15

Ok, cool.

Answer 16

should be it

Answer 17

Eh... Did not work :(

Answer 18

that makes me sad

Answer 19

What kind of file is it?

Answer 20

actually i know why it didnt work

Answer 21

its 10mb

Answer 22

O_O

Answer 23

I see. Heh. Is it an image or a PDF or what? If it's an image, it's probably a TIFF file. You can open it in Paint and then save as a PNG.

Answer 24

a pdf

Answer 25

Aha. Ok, so open the PDF, go to whatever page has the relevant graph, and then hit Alt+PrntScrn (not sure where the prntscrn or `print screen' button will be on your keyboard). Then, open Paint and paste.

Answer 26

k

Answer 27

Very nice :)

Answer 28

had to use gif but i got it

Answer 29

its the cherry stems on the top right i think also its flipped so what seems to be the x axis is the y axis

Answer 30

its the cherry stems on the top right i think also its flipped so what seems to be the x axis is the y axis

Answer 31

I think you may be supposed to estimate the slope of the tangent lines by finding the slope between the center and the endpoints on those hyperbolas.

Answer 32

alright thanks