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the sum of a number and twice its reciprocal is33/4. Find the number
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\[x + 2*x^-1 = 33/4\]
If you want it all to be in the power type ^{-1}
that should be x + 2* x^(-1) = 33/4
OR write: \[x + \frac{2}{x} = \frac{33}{4} \] \[\iff \frac{x^2 + 2}{x} = \frac{33}{4} \]
how do you do the fractions? i've been trying to do it but i cant
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\frac{a}{b} gives \[ \frac{a}{b} \]
And the if anf only if implication is \iff ... if anyone cares :(
\frac{2}{3}
It has to be in the equation editor
ehhh\[\frac{2}{2}\] ahhhhhh thanks :D \[\iff\] kewlll thanks a lot
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