Question

How do I solve for #12? I've attached the problem.

Answer 1

t = 8 is the maximum acceleration

Answer 2

maybe :)

Answer 3

haha thanks do you know how to do #12?

Answer 4

acceleration is any change in velocity; where the velocity is level, there is no acceleration.

Answer 5

we have the velocity changing at a rate of 1 in the first part.

zero in the next segment;

6/3 in the next = 2

and 4/1 in the last part.

so maybe between 8 and 9

Answer 6

the answer to 12 is D if that helps

Answer 7

i think your looking at #10

Answer 8

lol....without knowing what D stands for, it aint much help ;)

Answer 9

oh.... theres more if you scroll it lol

Answer 10

at t=8 the objects position was at x=10 ?? how do they figure that?

Answer 11

ok for #12
find equation for line from t=5 and t=8
slope is -2
v= 2 when t=5
2=-2*5 + b
b = 12
v(t) = -2t +12 for 5<t<8
now we need position function x(t) so integrate v(t)
x(t) = -t^2+12t +c
we know x(8) = 10
-8^2 +12*8 +c = 10
c = -22
find x(5)
-5^2 +12*5 -22 = 13