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OpenStudy (anonymous):
complete square root add what number to both sides to
x^2-6x=-8
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OpenStudy (amistre64):
what is a complete square?
OpenStudy (amistre64):
add (b/2)^2
OpenStudy (anonymous):
I did that I need a whole number I came up with 1 but it is not right
OpenStudy (anonymous):
-6/2 = -3
then you square that (-3)^2 = 9
OpenStudy (amistre64):
blext didnt get a 1 ;)
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OpenStudy (anonymous):
b=-6/2^2 = 36/4
OpenStudy (amistre64):
yes; and 36/4 = 9
OpenStudy (anonymous):
where so you get 36?
OpenStudy (amistre64):
6^2 = 36
--------- = 9
2^2 = 4
OpenStudy (anonymous):
formula x^-6x=-8
b=(-6/2)^2
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OpenStudy (anonymous):
36/4 =9 so I put 9 on each side of the equation?
OpenStudy (amistre64):
welll close;
b = -6; the number you wanna add to both sides is:
(b/2)^2
OpenStudy (amistre64):
yes; add 9 to both sides to complete the square
OpenStudy (anonymous):
okay that is not the example in my book
OpenStudy (amistre64):
there are many ways to get to the same answer; you gotta pick what works for you :)
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OpenStudy (anonymous):
this is true I am taking this test for my last time on my math lab and want to get the correct answers.
OpenStudy (amistre64):
the real solution is:
(bx/2ax)^2 but for the a=1 thats rather obiquitous. and the x's always cancel anyways.
OpenStudy (anonymous):
thank you
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