Question

what are the x-intercepts and minimum point(s) for the equation 3x^2-13x-10

Answer 1

minimum is when x = 13/6

Answer 2

Set the equation equal to zero to find the x intercepts. (When y=0 the graph is on the x axis). Using the quadratic equation you end up getting 5 and -2/3. (You can verify this yourself).

To find the minimum you can use calculus or algebra, but seeing as amistre64 answered this, he can explain it.

Answer 3

we can all explain it ;)

Answer 4

I can't do it with algebra :). Calculus drains all basic algebra from the brain. Haha.

Answer 5

dont it tho lol

Answer 6

the max/min of teh graph of a quadratic equation is where the graph curves back on itself and backs a peak or valley; that point is valled the vertex of the parabola

Answer 7

teh definition of a parabola also helps to define the vertex as the point in line between the focus and the directix such that the line from the focus to the directix is perpendicular it passes thru the vertex

Answer 8

the distance between all points of a parabola are equal distance to the focus and a perpendicular line to the directex; the shortest distance shich results is called the vertex

Answer 9

and yada yada yada ...lol

Answer 10

I don't know what method was used to get the 13/6 but one method is to\[d/dx=6x-13\]

Answer 11

-b/2a ;)

Answer 12

6x-13=0
x=13/6

Answer 13

the determinate of the quadratic formula is the x axis of symmetry if the parabola is oriented such that it is a function of x

Answer 14

(-b/2a, f(-b/2a)) are the coordinates of teh vertex....

Answer 15

there is also a method called the square root method that might be applicable

Answer 16

Refer to the plot attachment.

Answer 17

x=-.66666667 & x=5 the min (vertex) s x=2.1, y=-24.07